chain rule on derivatives and substitution rule of integrals
I am practicing the derivatives and integrals. I found this interesting
derivative.
$$y'=sin^3cose^{4x^2-5x}$$ $$y'=(sincose^{4x^2-5x})^3$$
$$y'=(3(sincose^{4x^2-5x})^2)(coscose^{4x^2-5x})(-sine{4x^2-5x})(e^{4x^2-5x}Lne(8x-5))$$
But I am lost with the steps for making the integral
Question
Can anyone help me with this without compute the solution?
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